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1897 Iowa gubernatorial election

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1897 Iowa gubernatorial election

← 1895 November 2, 1897 1899 →
 
Nominee L. M. Shaw Frederick Edward White
Party Republican Democratic
Popular vote 224,729 194,853
Percentage 51.27% 44.46%

County results
Shaw:      40-50%      50-60%      60-70%      70-80%
White:      40-50%      50-60%

Governor before election

Francis M. Drake
Republican

Elected Governor

L. M. Shaw
Republican

The 1897 Iowa gubernatorial election was held on November 2, 1897. Republican nominee L. M. Shaw defeated Democratic nominee Frederick Edward White with 51.27% of the vote.

General election

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Candidates

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Major party candidates

  • L. M. Shaw, Republican
  • Frederick Edward White, Democratic

Other candidates

  • S. P. Leland, Prohibition
  • Charles Lloyd, People's
  • John Cliggett, National Democratic
  • M. J. Kremer, Socialist Labor

Results

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1897 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican L. M. Shaw 224,729 51.27%
Democratic Frederick Edward White 194,853 44.46%
Prohibition S. P. Leland 8,243 1.88%
Populist Charles Lloyd 5,295 1.21%
Independent John Cliggett 4,296 0.98%
Socialist Labor M. J. Kremer 876 0.20%
Majority 29,876
Turnout
Republican hold Swing

References

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  1. ^ Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved August 8, 2020.