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Talk:Octadecagon

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Formula

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Is there a formula for this shape? --Rocket50 (talk) 00:49, 29 March 2009 (UTC)[reply]

For any number n, the vertices of a regular n-gon can be drawn on the unit circle with vertices at (cos(2πj/n),sin(2πj/n)) for 0≤j<n. Does that help? —Tamfang (talk) 00:41, 26 April 2012 (UTC)[reply]

A stub?

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Why it is a stub class? --Petrus3743 (talk) 15:30, 25 December 2016 (UTC)[reply]

Needs explanation

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Fragment

The regular octadecagon has Dih18 symmetry, order 36. There are 5 subgroup dihedral symmetries: Dih9, (Dih6, Dih3), and (Dih2 Dih1), and 6 cyclic group symmetries: (Z18, Z9), (Z6, Z3), and (Z2, Z1). These 15 symmetries can be seen in 12 distinct symmetries on the ...

needs axplanation.

Where from appears These 15 symmetries? Please, explain.
What 12 distinct symmetries? Please, explain.
Where 5 dihedral subgroups and 6 cyclic group symmetries appear in following text?
Where I can read about These 15 symmetries fnd 12 distinct symmetries?

Jumpow (talk) 11:57, 11 January 2017 (UTC)[reply]